## How to print a matrix of size n*n in spiral order using C#?

To rotate a matrix in spiral order, we need to do the following until all the inner matrix and the outer matrix are covered −

Step1 − Move elements of top row
Step2 − Move elements of last column
Step3 − Move elements of bottom row
Step4 − Move elements of first column
Step5 − Repeat above steps for inner ring while there is an inner matrix

``````using System;
namespace CsharpCode_ConsoleApplication{
public class Matrix{
public void PrintMatrixInSpiralOrder(int m, int n, int[,] a){
int i, k = 0, l = 0;
while (k < m && l < n){
for (i = l; i < n; ++i){
Console.Write(a[k, i] + " ");
}
k++;
for (i = k; i < m; ++i){
Console.Write(a[i, n - 1] + " ");
}
n--;
if (k < m){
for (i = n - 1; i >= l; --i){
Console.Write(a[m - 1, i] + " ");
}
m--;
}
if (l < n){
for (i = m - 1; i >= k; --i){
Console.Write(a[i, l] + " ");
}
l++;
}
}
}
}
class CsharpCode_Program{
static void Main(string[] args){
Matrix m = new Matrix();
int R = 3;
int C = 6;
int[,] aa = { { 1, 2, 3, 4, 5, 6 },
{ 7, 8, 9, 10, 11, 12 },
{ 13, 14, 15, 16, 17, 18 } };
m.PrintMatrixInSpiralOrder(R, C, aa);
}
}
}``````