C-Sharp

Generate a random character C# with Example



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Generate a random character C# with Example

Generate a random letter between a and z by using the Next() overload for a given range of numbers, then 
converting the resulting int to a char 
Random rnd = new Random(); 
char randomChar = (char)rnd.Next('a','z'); 
//'a' and 'z' are interpreted as ints for parameters for Next()

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