Creating an array of sequential numbers C# with Example

LINQ provides a method that makes it easy to create a collection filled with sequential numbers. For example, you 
can declare an array which contains the integers between 1 and 100. 
The Enumerable.Range method allows us to create sequence of integer numbers from a specified start position and 
a number of elements. 
The method takes two arguments: the starting value and the number of elements to generate. 
Enumerable.Range(int start, int count) 
Note that count cannot be negative. 
Usage: 
int[] sequence = Enumerable.Range(1, 100).ToArray(); 
This will generate an array containing the numbers 1 through 100 ([1, 2, 3, ..., 98, 99, 100]). 
Because the Range method returns an IEnumerable, we can use other LINQ methods on it: 
int[] squares = Enumerable.Range(2, 10).Select(x => x * x).ToArray(); 
This will generate an array that contains 10 integer squares starting at 4: [4, 9, 16, ..., 100, 121].